Physics Self-Test - Page 14
103- Dielectrics are _________________
- a. Conducting substances
- b. Non-conducting substances
- c. Semi-conducting substances
- d. None of the option
Explanation: Dielectrics are electrical insulators (non-conducting substances) that do not have free charge carriers for conduction, but can sustain an internal electric field via microscopic polarization.
104- The electric potential inside a conducting sphere _________________
- a. is zero
- b. increases from centre to the surface
- c. decreases from centre to the surface
- d. remains constant from centre to the surface
Explanation: Inside a charged conducting sphere, the internal electric field is zero ($E = 0$). Since $E = -\frac{dV}{dr}$, the potential gradient must be zero, meaning the electric potential remains constant from the center to the surface ($V = \frac{q}{4\pi\varepsilon_0 R}$).
105- If VA and VB are the potentials of the two points A and B, what will be the correct relation between the electric field and the potential difference between the points? The distance between the points is d.
- a) VA - VB = Ed
- b) VB - VA = Ed
- c) VA - VB = E/d
- d) VA - VB = d/E
Explanation: Electric field lines always point in the direction of decreasing potential. Therefore, point A is at a higher potential than point B ($V_A > V_B$). The magnitude of the drop over distance $d$ in a uniform field is simply $\Delta V = Ed$, giving $V_A - V_B = Ed$.
106- By performing a set of experiments, a scientist found that the electric field between two points A and B is zero. What can he conclude regarding the potential of the two points?
- a) VA=0, VB=0
- b) VA > VB
- c) VA + VB
- d) VA = VB
Explanation: Since $E = -\frac{\Delta V}{\Delta r}$, if the electric field $E$ between two points is zero, there is no change in potential along that path ($\Delta V = 0$). Hence, the potential at both locations must be identical ($V_A = V_B$).
107- If a charged body is moved in an electric field against the Coulomb force, then _________
- a) Work is done on the body by an external agent
- b) Work is done by the electric field
- c) Electric field intensity decreases
- d) The total energy of the system decreases
Explanation: Moving a charge against the opposing electrostatic Coulomb force requires an external force to counteract the field. Therefore, positive work is done *on* the system by an external agent, increasing its electrostatic potential energy.